Algebra problems please help 10 pts best answer

[From: ] [author: ] [Date: 11-10-20] [Hit: ]

7a - 3a + 12 = -242. Combine terms.4a + 12 = -243. Subtract 12 from both sides.4a = -364. Divide both sides by 4.......

2. Subtract 2y from both sides.
Y + 6 = -4 + 2 (or 2 - 4)
3. Subtract 6 from both sides.
Y = -8

7a-3(a-4)=-24
1. Simplify parenthesis.
7a - 3a + 12 = -24
2. Combine terms.
4a + 12 = -24
3. Subtract 12 from both sides.
4a = -36
4. Divide both sides by 4.
A = -9

3(x-3)-4x+14=27
1. Simplify parenthesis.
3x - 9 - 4x + 14 = 27
2. Combine terms.
5 - x = 27
3. Subtract 5 from both sides.
-x = 22
X = -22

Hope this helps!

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I'm assuming you're trying to solve for the variables

3(y + 2) = 2(y - 2) + 2

expand

3y + 6 = 2y - 4 + 2

move variables to one side

3y - 2y = -4 + 2 - 6

add the terms

y = -8

Do the same for the other equations

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distribute in every problem first...like for example in 3(y+2)= 2(y-2)+2 you would get 3y +6=2y-4 +2
then combine like terms

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1.
3(y+2)=2(y-2)+2
3y+6=2y-4+2
y=-8
2.
7a-3(a-4)=-24
7a-3a+12=-24
4a=-36
a=-9
3.
3(y+2)=2(y-2)-2
3y+6=2y-4+2
3y+6=2y-2
y=-8

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1. 3y+6 = 2y-2
Y+6 = -2
y = -8

2. 4a+12=-24
4a=-36
a=-9

3. -x+5=27
-x=22
x=-22

4. And 1. Are the same

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yes

12

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