What is the equation of the right bisector of AB

A(-7,-1)
B(5,5)
midpoint of AB/point on the right bisector (-1,2)
slope of the right bisector -1/2

Am I correct if not, please correct me.
y=m(x-x1)+y1
y-y1=m(x-x1)
y-2=-1/2(x-(-1))
y-2=-1/2x+2
y=-1/2x+2

The midpoint is (-1, 2) as you said.

The slope of line AB is (5 + 1) / (5 + 7) = 6/12 = 1/2
So the slope of the right bisector is -2

y - 2 = -2(x + 1)

y = -2x