How would you solve this equation

Graphically: x^2/3+x^1/3-6=0

x^2/3+x^1/3-6=0

ley x^1/3 = y

y^2+y - 6 = 0

y^2+3y-2y-6 = 0

y(y+3)-2(y+3) = 0

(y-2)(y+3) = 0

y = 2 or -3

so x = 8 or -27

I believe;

X ^ (2/3) + X ^ (1/3) - 6 = 0
X ^ (2/3) + X ^ (1/3) = + 6 ( Subtracted 6 )
Add the exponents. .. so two thirds plus one third = 1 whole

X ^ 1 = 6
So X = 6.

I guess:

x^(2/3) + x^(1/3) = 6

Download Graph 4.4 from www.padowan.dk for free.

On "FunctionI Insert relation", type x^(2/3) + x^(1/3) = 6, then OK".

You'll see a vertical line at x = 8, answer!

I would solve it by asking on Yahoo Answers.