Pretty sure if this is possible a trig identity is used but I have no idea which one.
Also wanna add that yahoo thought this belonged in religion and spirituality...
Also wanna add that yahoo thought this belonged in religion and spirituality...
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Not a trig identity, an algebra identity.
Difference of Cubes:
α³ - ß³ = (α - ß)(α² + αß + ß²)
x³ - 2³ = (x - 2)(x² + 2x + 4)
lim{x→2} sin(x-2)/(x-2) → 1, so you're left with lim{x→2} 1/(x² + 2x + 4) = 1/12
Difference of Cubes:
α³ - ß³ = (α - ß)(α² + αß + ß²)
x³ - 2³ = (x - 2)(x² + 2x + 4)
lim{x→2} sin(x-2)/(x-2) → 1, so you're left with lim{x→2} 1/(x² + 2x + 4) = 1/12
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It's zero
Sin(0)=0
0 divided by anything is 0
You're over thinking it
Sin(0)=0
0 divided by anything is 0
You're over thinking it
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Hello. Knok me to icq 5 66666 269 to get full solution.