Find the equation of the tangent to the graph at the indicated point.

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Find the equation of the tangent to the graph at the indicated point.

[From: ] [author: ] [Date: 11-10-29] [Hit: ]

f(x) = x^2 − 8x; a = −1

f'(x) = 2x-8
f'(-1) = -10
f(-1) = 1+8 = 9
Point is (-1,9)
y-9 = -10(x+1)
y-9 = -10x-10
y = -10x - 1

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