Please, solve this for x and show me how

-4/((х-4)*(х-6)) = -4/((х-3)*(х-5))

Well, lets just take this one step at a time. First, I would probably want to simplify those denominators. So lets multiply those values together:
-4/((x-4)(x-6)) = -4/((x-3)(x-5))
-4/(x^2-10x+24) = -4/(x^2-8x+15)

Next, you multiply each side by the other's denominator:
-4/(x^2-10x+24) = -4/(x^2-8x+15)
-4(x^2-8x+15) = -4(x^2-10x+24)

Now I would get rid of those pesky -4's by dividing both sides by that value:
-4(x^2-8x+15) = -4(x^2-10x+24)
x^2-8x+15 = x^2-10x+24

Now, you get the x's on one side of the equal sign and the non-variables on the other, and solve for x:
x^2-8x+15=x^2-10x+24
2x=9
x=9/2

Hope this helps.