a.) 4, 4.5, 4.75
b.) √19, √33, √35
__ __ __
c.) 3.3 , 4.3, 4.9
d.) √41, √44, √47
please explain how to do this
b.) √19, √33, √35
__ __ __
c.) 3.3 , 4.3, 4.9
d.) √41, √44, √47
please explain how to do this
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Answer is B.
a) Can be expressed as a simple fraction
b) Cannot
c) Can also be expressed as a simple fraction
d) Cannot BUT the values do not fall between 3 and 6, for example, the square root of 41 is greater than 6!
a) Can be expressed as a simple fraction
b) Cannot
c) Can also be expressed as a simple fraction
d) Cannot BUT the values do not fall between 3 and 6, for example, the square root of 41 is greater than 6!
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Well, you can rule out a and c right away, because none of those number are irrational.
To get the final answer, you need to figure out which of the sets of square roots falls within the
correct range. To do this realize that if 3 <= √x <= 6, this would require that
9 <= x <= 36.
Only b has numbers in the correct range, so it is the answer.
To get the final answer, you need to figure out which of the sets of square roots falls within the
correct range. To do this realize that if 3 <= √x <= 6, this would require that
9 <= x <= 36.
Only b has numbers in the correct range, so it is the answer.
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B
it can't be the terminating decimals because they're rational. The only candidates here are the irrational roots.
since 3^2 = 9 and 6^2 = 36, √41 > 6
apply the same kind of thinking to the numbers in B and they are all between 3 and 6
it can't be the terminating decimals because they're rational. The only candidates here are the irrational roots.
since 3^2 = 9 and 6^2 = 36, √41 > 6
apply the same kind of thinking to the numbers in B and they are all between 3 and 6
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an irrational number is a number that cannot be written as a fraction, terminating decimal or repeating decimal. so a and c are automatically out. d is not correct either because those roots all yield numbers bigger than 6. so your answer is b.