Can you answer this amths question pls|

The first three terms of an arithmetic sequence are p, 5p-8 and 3p+8 respectively.


p-4

find the value of the 40th term of the series.

Since it is arithmetic, consecutive terms have a common difference:

(5p - 8) - p = (3p + 8) - (5p - 8)
4p - 8 = -2p + 16
6p = 24
p = 4

Thus, a[1] = 4 and a[2] = 5*4 - 8 = 12, meaning d = 12 - 4 = 8.

a[n] = a[1] + (n - 1)d
a[40] = 4 + 39*8 = 316