A point P(-√3/2, 1/2) is given. Suppose that P is the terminal point determined by t. Find sin t, cos t and..

tan t.

please explain how to do this..

Tan(t) = y/x
Tan(t) = 1/2 // -sqrt(3)/3 = 1/ - sqrt(3) = sqrt(3)/-3

Now the x and y values must be conbined to find the hypotenuse.

y^2 + x^2 = hypotenuse squared.
(1/2)^2 + [ - sqrt(3) ] ^2 = z^2
1/4 + 3/4 = 1
z^2 = 1
z= sqrt(1) = 1

Sin(t) = y/z = 1/2/1 = 1/2

Cos(t) = x/z = -sqrt(3)/2 / 1 = -sqrt(3)/2

sin(t) = 1/2

cos(t) = -√3/2

tan(t) = -√3/3