HOME > > Can someone help me with/teach me my math? I've missed some school and im not sure how to do it.
Can someone help me with/teach me my math? I've missed some school and im not sure how to do it.
[From: ] [author: ] [Date: 11-11-26] [Hit: ]
The roots are -2/3, +1/2 (twice), and two imaginary roots.Hoping this helps!Good luck!-The Rational Zero TheoremIf P(x) has integer coefficients,......
(3x+2)(2x-1)(2x^3-x^2+2x-1)... Factor by grouping
2x^3-x^2 +2x -1= X^2(2x-1)+ 1(2x-1)= (x^2+1)(2x-1)
Now factored completely! (x^2+ 1) is the prime quadratic factor in your question.
(3x+2)(2x-1)^2(x^2+1)
In summary , the function is fifth degree. The roots are -2/3, +1/2 (twice), and two imaginary roots.
Hoping this helps!
Good luck!
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The Rational Zero Theorem
If P(x) has integer coefficients, and p/q is a rational zero of P(x), then p is a factor of the leading coefficient (the coefficient on the highest power) and q is a factor of the constant coefficient.
leading coefficient is 12, factors could be 1,2,3,4,6
constant is 2, factor could be 1,2
so the rational zeros could 1/2, 1/2. 2/1. 2/2
3/1, 3/2
4/1, 4/2
6/1, 6/2
or
± 1/2 , ±2, ±1, ±3, ±3/2, ±4, ± 6
you can use long division, synthetic division, by trial and error, for me, I use
http://www.wolframalpha.com/input/?i=fin…
solutions
1/2 and -2/3
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