f(x)=-6e^(4+x)+18
2.) Find f(1) given the function f(x)=-5e^(3-4x)+10
3.) Find the domain of the function g(x)=log(base)3(x+2)+1
i have the answer key but I'm not sure how they got the answer Thank you!!
2.) Find f(1) given the function f(x)=-5e^(3-4x)+10
3.) Find the domain of the function g(x)=log(base)3(x+2)+1
i have the answer key but I'm not sure how they got the answer Thank you!!
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1.when you insert -2 into each x in your function, you come up with f(-2) = 6e^(4+-2)+ 18 = 6 e^2 + 18 or approximately 62.334
2. f(1) = 5 e^(3-4(1)) + 10 = 5 e^(-1) + 10 or approximately 11.839
3. domain of g(x) = log sub3 (x+2) +1 = [-1, infinite] <-- I believe this is correct
2. f(1) = 5 e^(3-4(1)) + 10 = 5 e^(-1) + 10 or approximately 11.839
3. domain of g(x) = log sub3 (x+2) +1 = [-1, infinite] <-- I believe this is correct
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For something like f(-2), it's as simple as plugging in negative 2 everywhere you see an x, then solving.