URGENT: Help with finding z-statistic?!

Here's the information:
One-third of all ex-convicts return to jail within 3 years. One state is trying a new rehabilitation system fr its prisoners. After the release of 50 prisoners who had participated in the new system, only 13 returned within 3 years. the null and alternative hypotheses are: Ho: p = 1/3 vs. Ha: p ≠ 1/3.

Question 1:
To test the null hypothesis, the approximate observed value of the z-statistic is:

For this question I use the formula

z = (p̂ - p) / (sqrt[p(1-p)] / n)
z = (.26 - .33) / (sqrt[.33*.66)] / 50) = -1.06 < this is my answer (the key says it's -1.10)

Question 2:
What is the approximate p-value of the observed z-statistic?

I'm stuck here.
I think I need to use normcdf(-1.06, (9^9)), but using this I get .853 and the answer key says it's .27. What am I doing wrong here? I know it's two tailed because the alternative is ≠, but even if I multiply .853 by 2 I'm still not getting the correct answer.

Any and all help is appreciated. The one who explains it best and correctly gets the ten points. Thank you!!

The trouble is with your approximation of 1/3. Calculate as below.
z = (13/50 - 1/3) / (sqrt[1/3*2/3)] / 50)
The p-value (for z = -1.10) is 0.1357*2 = 0.2714