Can somebody please explain to me how to solve this

8cosx-1=0

THANKS! This will help guide me with the rest of the similar problems I have.

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8cos(x) - 1 = 0
8cos(x) = 1
cos(x) = 1/8 ← This tells you that cosine is positive so that x is a 1st or 4th quadrant angle
x = arccos(1/8) = 1.445 rad            ← 1st quadrant
                        or
       2π - 1.445 = 4.838 rad            ← 4th quadrant


                  ANSWER
        x = 1.445 rad, 4.838 rad


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x = 2 pi n + cos^-1 (1 / 8) or x = 2 pi n - cos^-1 (1 / 8)
so basically... x is approx 6.28319 n - 1.44547 or x is approx 6.28319 n + 1.44547.

cosx = 1/8
x = 82.819 or 277.18 degrees