Verify the identity: sin^1/2x cosx - sin^5/2x cosx = cos^3x √sinx
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Verify the identity: sin^1/2x cosx - sin^5/2x cosx = cos^3x √sinx

[From: ] [author: ] [Date: 11-12-21] [Hit: ]
sin^1/2xcos^3x.YOull find out that factoring when you are trying to verify an identity becomes very helpful because it helps simplifies the problem down to something that you can recognize.......
Help with this problem, please!!!!

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okay for sin^5/2x you can split that up into sin^1/2x*sin^2x


sin^1/2xcosx-sin^1/2x*sin^2xcosx

now you can factor out a sin^1/2xcosx

sin^1/2xcosx(1-sin^2x)

remember identites: sin^2x+cos^2x=1 so 1-sin^2x=cos^2x

sin^1/2xcosx(cos^2x)

now multiply everything out

sin^1/2xcos^3x.

YOu'll find out that factoring when you are trying to verify an identity becomes very helpful because it helps simplifies the problem down to something that you can recognize.

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sin^1/2x cosx - sin^5/2x cosx
= sin^1/2x cosx (1-sin^2x)
= sin^1/2x cosx cos^2x
= cos^3x √sinx
1
keywords: identity,Verify,sinx,cosx,cos,radic,sin,the,Verify the identity: sin^1/2x cosx - sin^5/2x cosx = cos^3x √sinx
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