X^3-3x^2+2 find the derivative how is the derivative 6 i do not understand that

HOW DO YOU SOLVE TO GET 6

Derivatives are found with the difference quotient

f(x) = x^3 - 3x^2 + 2
f(x + h) = (x + h)^3 - 3 * (x + h)^2 + 2 = x^3 + 3x^2 * h + 3x * h^2 + h^3 - 3x^2 - 6xh - 3h^2 + 2

(f(x + h) - f(x)) / h =>
(x^3 + 3x^2 * h + 3x * h^2 + h^3 - 3x^2 - 6xh - 3h^2 + 2 - x^3 + 3x^2 - 2) / h =>
(3x^2 * h + 3x * h^2 + h^3 - 6xh - 3h^2) / h =>
3x^2 + 3xh + h^2 - 6x - 3h

Now, let h go to 0

3x^2 + 3x * 0 + 0^2 - 6x - 3 * 0 =>
3x^2 - 6x

So the derivative of x^3 - 3x^2 + 2 is 3x^2 - 6x

3x^2 - 6x = 6
x^2 - 2x = 2
x^2 - 2x - 2 = 0
x = (2 +/- sqrt(4 + 4 * 2)) / 2
x = (2 +/- 2 * sqrt(1 + 2)) / 2
x = 1 +/- sqrt(3)

I don't know if that's what you're asking, but the derivative of x^3 - 3x^2 + 2 is 6 only when x = 1 +/- sqrt(3)

Did they tell you to find the derivative of this equation at a specific point?

The derivative of the equation you gave us is 3x^2-6x.

x^3-3x^2+2
derivative should be 3x^2-6x

3x^2 -6x is the derivative. So for that to equal 6 they must be talking bout at a certain point. So solve 3x^2-6x-6.