Solve the indefinite integral Xe^((-x^2)/2)

[From: ] [author: ] [Date: 12-02-21] [Hit: ]

using the substitution medthod

∫x*e^(-x²/2) dx

u = -x²/2

-du = x dx

-∫e^(u) du = -e^(-x²/2) + C

INTEGRAL[x*e^(-x^2/2) dx]
u=x^2/2; du=x dx
INTEGRAL[e^-u du]
-e^-u + C
-e^(-x^2/2) + C

keywords: Xe,indefinite,the,integral,Solve,Solve the indefinite integral Xe^((-x^2)/2)