I have tried to factor this and I do not understand how to factor a cube????
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c(c-8)(c+6)
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Normally I have to do a bit of guess work to find the first factor, then it becomes easy but with this one it's dead easy, notice there is no numerical term so everything has c as a factor.
c(c^2 - 2c - 48)
now it's just factorising a straight forward quadratic.
Two numbers that are two apart and multiply to give 48, well we know from our times table that that's 6*8, now it's -2 so the 8 must be the -ve one. They must be opposite signs as the numerical term is negative.
(c-8)(c+6) = c^2 + 6c -8c - 48 = c^2 -2c - 48 - so yes that works.
Your factors then are c(c-8)(c+6)
hope this helps
c(c^2 - 2c - 48)
now it's just factorising a straight forward quadratic.
Two numbers that are two apart and multiply to give 48, well we know from our times table that that's 6*8, now it's -2 so the 8 must be the -ve one. They must be opposite signs as the numerical term is negative.
(c-8)(c+6) = c^2 + 6c -8c - 48 = c^2 -2c - 48 - so yes that works.
Your factors then are c(c-8)(c+6)
hope this helps
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c(c^2-2c-48)
c(c^2+6c-8c-48)
c[c(c+6)-8(c+6)]
c(c+6)(c-8)
c(c^2+6c-8c-48)
c[c(c+6)-8(c+6)]
c(c+6)(c-8)
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c³- 2c² - 48c = c(c² - 2c - 48)
=> c(c - 8)(c + 6)
:)>
=> c(c - 8)(c + 6)
:)>