Partial Fraction..helpp!!

Resolve into partial fraction
x-3/(2x+1) (x-4)

x-3/(2x+1) (x-4)=A/(2x+1)+B/(x-4)
x-3 = A(x-4)+B(2x+1)
Let x=4
1=B*9
B=1/9
Let x=-1/2
-3.5=A*(-4.5)
A=3.5/4.5=7/9
Answer:
7/[9(2x+1)]+1/[9(x-4)]

x-3/2x^2-7x-4