I'm really stuck on this and I could use some help. I nedd to reduce this fraction to a simpler form: x^3(x-2)(x-3)(x+2) / (x^2+1)(x-1)(x+1)(x-3). I know the x-3 on top and bottom cancel, but after that I'm stuck on what to do. Any help would be greatly appreciated!
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x^3(x-2)(x-3)(x+2) / (x^2+1)(x-1)(x+1)(x-3)
= x^3(x-2)(x+2) / (x^2+1)(x-1)(x+1)
This is the simplest. If you reduce something to its factors, and you can't cancel out any factors, then that's it; that's the simplest.
= x^3(x-2)(x+2) / (x^2+1)(x-1)(x+1)
This is the simplest. If you reduce something to its factors, and you can't cancel out any factors, then that's it; that's the simplest.
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hey there here is what i got: i tried expanding the bottom and top and i got it down to:
(x^5 -4x^3) / (x^4 -1)
u can take out x^3 from the top but there is no point really...
(x^3(x^2- 4)) /(x^4 -1)
thats the most simplest i can think of!! hope it helps :D
(x^5 -4x^3) / (x^4 -1)
u can take out x^3 from the top but there is no point really...
(x^3(x^2- 4)) /(x^4 -1)
thats the most simplest i can think of!! hope it helps :D
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x^3(x^2 - 4)/ x^4 -1
{Use difference of 2 squares
(x+2)(x-2) = x^2 - 4
(x+1)(x-1) = x^2 - 1
(x^2 - 1)(x^2 + 1) = x^4 - 1}
{Use difference of 2 squares
(x+2)(x-2) = x^2 - 4
(x+1)(x-1) = x^2 - 1
(x^2 - 1)(x^2 + 1) = x^4 - 1}
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Why don't you try and expand out the entire numerator and denominator, and then re-factor them and look for cancles?