I got the answer to ((lnxcosx + sinx) / x), but how is the answer simplified to cosx + 1/x? Show me how please
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f'(x) = cosx + 1/x in one step
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Not sure what you did?
Just take the derivative of each term separately
Derivative of sinx = cosx
Derivative of ln(x) = 1/x
So your answer is cosx + 1/x.
Just take the derivative of each term separately
Derivative of sinx = cosx
Derivative of ln(x) = 1/x
So your answer is cosx + 1/x.