Find the sum s for other telescoping series for : ln 1/2 + ln 2/3 + ln 3/4
Favorites|Homepage
Subscriptions | sitemap
HOME > > Find the sum s for other telescoping series for : ln 1/2 + ln 2/3 + ln 3/4

Find the sum s for other telescoping series for : ln 1/2 + ln 2/3 + ln 3/4

[From: ] [author: ] [Date: 12-04-09] [Hit: ]
.. = ln(1) - ln(2) + ln(2) - ln(3) ...as n -> ∞,......
This actually isn't a telescoping series, even though it appears to be one. You can rewrite it as
ln((1/2)(2/3)(3/4)...) = ln(1/n)

As n -> ∞, 1/n -> 0, and ln(0) is undefined. So the sum doesn't converge.

Even if you broke it up so it did telescope:
ln(1/2) + ln(2/3) + ... = ln(1) - ln(2) + ln(2) - ln(3) ... = ln(1) - ln(n) = -ln(n)

as n -> ∞, -ln(n) -> -∞ so the sum doesn't converge.

-
......... n ... .. .. .. .. .. .. .. . n
S(n) = ∑ ln( k/(k+1) ) = ln ( П ( k/(k+1) ) ) = ln(1/n+1)
......... k=1 .. .. .. .. .. .. .. . k=1
1
keywords: telescoping,other,sum,for,Find,ln,the,series,Find the sum s for other telescoping series for : ln 1/2 + ln 2/3 + ln 3/4
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .