4
-----
3x
1
-------
x+1
1
-------------
2x^2+2x
I know x+1 is part of it but the 2x and 3x are tripping me up.
It's also an equation but it wouldn't type out right. It's the first fraction minus the second fraction equals the third fraction.
-----
3x
1
-------
x+1
1
-------------
2x^2+2x
I know x+1 is part of it but the 2x and 3x are tripping me up.
It's also an equation but it wouldn't type out right. It's the first fraction minus the second fraction equals the third fraction.
-
L C D of 3x, x+1, 2x(x+1)
taking (x+1) as common from 2nd & 3rd denominator 3x, 1, 2x
taking x common gives 3, 1, 2
remaining terms are primes[3,2]
so
LCD = (x+1)* (x)* (3*2)]
= 6 x (x+1)
taking (x+1) as common from 2nd & 3rd denominator 3x, 1, 2x
taking x common gives 3, 1, 2
remaining terms are primes[3,2]
so
LCD = (x+1)* (x)* (3*2)]
= 6 x (x+1)