Evaluate the integral. ʃ from 2 to 3 (x^2/x^3-2) dx

Can anyone help?

x^2 * dx / (x^3 - 2)

u = x^3 - 2
du = 3x^2 * dx

(1/3) * du / u

Integrate

(1/3) * ln|u| + C =>
(1/3) * ln|x^3 - 2| + C =>
(1/3) * ln|3^3 - 2| - (1/3) * ln|2^3 - 2| =>
(1/3) * ln|27 - 2| - (1/3) * ln|8 - 2| =>
(1/3) * ln(25) - (1/3) * ln(6) =>
(1/3) * ln(25/6)