Ok Megan---here we go again.
All logs are to base 10 I'm assuming...but as long as all are to the same base everything works.
By properties of logs the RHS can be converted to log[b/x^k].
Now take both sides as exponents of your base and you'll end up with
y = b/x^k as your answer.
All logs are to base 10 I'm assuming...but as long as all are to the same base everything works.
By properties of logs the RHS can be converted to log[b/x^k].
Now take both sides as exponents of your base and you'll end up with
y = b/x^k as your answer.
-
log y = log b - log x^k = log (b/(x^k))
y = b/(x^k)
y = b/(x^k)