Can somebody help me with this trig problem

[From: ] [author: ] [Date: 12-04-27] [Hit: ]

Sin100°Cos10°-Cos100°Sin10°?

The compound angle formula sin(A−B) = sinAcosB − cosAsinB can be used here.
Sin100°Cos10°-Cos100°Sin10° = sin(100°−10°) = sin90° = 1.

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