4x^2 − 19x + 12 and # 2 )x^2 + 23x + bx + 23b (Please help me I'm lost)

Factor the polynomial completely. That is, once you are finished factoring, none of the factors you obtain should be factorable..

x = b +- sqrt(b^2 - 4ac)
-------------------------------
2a

1. 4x^2 - 19x + 12

(4x - 3)(x - 4) = 0

2. x^2 + 23x + bx + 23b

(x + something1)(x + something2
last term is 23b -- only thing that can multiply into 23 ... is 23.
(x + b)(x + 23)

OMG by seeing this only I m lost :)