3 1/4 – 1 3/4 = ?
how woud it work here? please and thank you
how woud it work here? please and thank you
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You need to convert the fractions into improper fractions to solve.
When you have a+b/c, that can become an improper fraction by multiplying the whole number by the denominator and adding it to the numerator.
a + b/c = (ac + b)/c
For instance
1 1/2 = (1*2 + 1)/2 = 3/2
You "borrow" the whole number to turn the mixed numeral into an improper fraction.
3 1/4 = (3*4 + 1)/4 = 13/4
1 3/4 = (1*4 + 3)/4 = 7/4
Now you can subtract:
13/4 - 7/4 = 6/4
6/4 can be reduced to 3/2, or (as in my example) 1 1/2.
When you have a+b/c, that can become an improper fraction by multiplying the whole number by the denominator and adding it to the numerator.
a + b/c = (ac + b)/c
For instance
1 1/2 = (1*2 + 1)/2 = 3/2
You "borrow" the whole number to turn the mixed numeral into an improper fraction.
3 1/4 = (3*4 + 1)/4 = 13/4
1 3/4 = (1*4 + 3)/4 = 7/4
Now you can subtract:
13/4 - 7/4 = 6/4
6/4 can be reduced to 3/2, or (as in my example) 1 1/2.