Calculate the discriminant. Show your work!
5x² - 11x – 2 = 0
5x² - 11x – 2 = 0
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If you take a look at the quadratic equation, the part of the equation that is under the square root sign is call the discriminant. It tells you what the nature of the roots of the equation are.
So what you are asked to ind is b^2 - 4ac where a=5, b=-11 and c = -2 for this equation
(-11)^2 - 4 (5)(-2) = 121 + 40 = 161
So the discriminant is 161.
Since it is greater than zero, there will be two real roots.
So what you are asked to ind is b^2 - 4ac where a=5, b=-11 and c = -2 for this equation
(-11)^2 - 4 (5)(-2) = 121 + 40 = 161
So the discriminant is 161.
Since it is greater than zero, there will be two real roots.
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The discriminate for a quadratic function in the form: y=ax²+bx+c is b²-4ac.
In this example, a=5, b=-11, and c=-2.
Plugging those in, you get (-11)²-4(5)(-2)
-11²=121 and -4*5*-2=40
(because I included the minus (-) sign in the equation, make sure you add)
121+40=161
There's your answer :D
In this example, a=5, b=-11, and c=-2.
Plugging those in, you get (-11)²-4(5)(-2)
-11²=121 and -4*5*-2=40
(because I included the minus (-) sign in the equation, make sure you add)
121+40=161
There's your answer :D
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The discriminant of a quadratic ax² + bx + c is b² - 4ac. In this case a = 5, b = -11, and c = -2. So the discriminant is (-11)^2 - 4(5)(-2) = 121 +40 = 161.
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a = 5, b = - 11, c = - 2
b^2 - 4*a*c = 121 - 4*(5)*(- 2) = 161, answer!
b^2 - 4*a*c = 121 - 4*(5)*(- 2) = 161, answer!
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161
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