In a simple random sample of 298 students at a college, 87 reported that they have at east $1,000 of credit ca

In a simple random sample of 298 students at a college, 87 reported that they have at east $1,000 of credit card debt. What is the 99% confidence interval for the percent of all the students at that college who have at least $1000 in credit card debt?


(26.5, 31.9)
(24.8, 33.6)
(22.4, 36.0)
(21.8, 36.6)

mean ≈ 29.2%
SD = sqrt(pq/n) = sqrt(87/298 *211/298 *1/298) = 2.63%
z-score for 995 confidence interval = ±2.58
29.2% ± 2.63*2.58 = (22.4, 36.0) <---------