I think that question must be solved by contradiction method..
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There are lots of solutions to this on the internet, including some on youtube where they walk you thru it. Here is another:
http://www.grc.nasa.gov/WWW/K-12/Numbers…
http://www.grc.nasa.gov/WWW/K-12/Numbers…
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A proof by contradicts works by first assuming what you wish to show is false. Thus assume that the square root of 3 is rational. Then you can write:
3√=pq
where p and q are integers with no factors in common (and q non-zero).
See if you can derive a contradiction from this (HINT: see if you can find a common factor which would be a contradiction).
3√=pq
where p and q are integers with no factors in common (and q non-zero).
See if you can derive a contradiction from this (HINT: see if you can find a common factor which would be a contradiction).
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Well, you know it is irrational because √3 = 1.732050.....
It is not a whole number (obviously) and it is not a rational number because you can't express it as a simple fraction. It is a long decimal, so it is irrational.
It is not a whole number (obviously) and it is not a rational number because you can't express it as a simple fraction. It is a long decimal, so it is irrational.
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@ Really Dakines
how is that a proof ???
how is that a proof ???