Please solve algibra 2 problem
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Please solve algibra 2 problem

[From: ] [author: ] [Date: 12-06-21] [Hit: ]
when finding the vertical asymptote, your basically finding the zero of the denominator, so just factor out x^2+6x+8. there are two vertical asymptoes at -2 and -4.......
1. The price per person of renting a bus varies inversely wth the number of people renting the bus. it costs $32 per person if 68 people rent the bus. About how much will it cost per person if 99 people rent the bus?
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#2.Identify the vertical asympotote(s) of the graph of the function.
f(x)=4x+7/over/ x^2+6x+8
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#3. Multiply the expression. simplify the resilt.
d^2 /over/ ef * 5e^5f /over/ 4d
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#4. Multiply the expression. simplify the resilt.
n^2 -9 /over/ n+3 * n /over/ 2n-6

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1.

68 -> 32$

99 -> x$

x = (99 * 32)/68 = 47$

2.

f(x) = (4x + 7)/x² + 6x + 8

x² + 6x + 8 = 0 for the vertical asymptotes.

x = -2 and x = -4 are both V.A

3.

(d²/fe) * (5fe^5/4d) = '5de^4)/4

4.

(n² - 9)/(n + 3) * n/(2n - 6) = (n - 3)(n + 3)/(n + 3) * n/2(n - 3) = n/2

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2. when finding the vertical asymptote, your basically finding the zero of the denominator, so just factor out x^2+6x+8. there are two vertical asymptoes at -2 and -4.
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