Ok i have base 5^x^2+6=5^-5x. this is logarithms using exponential functions.

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Ok i have base 5^x^2+6=5^-5x. this is logarithms using exponential functions.

[From: ] [author: ] [Date: 12-06-22] [Hit: ]

-Please use parenthesis. It appears to be a mess without parenthesis.For example,LHS could mean 5^(x^2),(5^x)^2 or 5^(6+x^2).from a^x =a^y ,......

How do i solve :)

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i guess it is 5^(x^2+6) and not (5^(x^2))+6.
In that cae we must have x^2+6 = -5x or 5^x^2+5x+6 = 0 so (x+3)(x+2) = 0 means x = -2 or -3.

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Please use parenthesis. It appears to be a mess without parenthesis.

For example,

LHS could mean 5^(x^2), (5^x)^2 or 5^(6+x^2).

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if u meant 5^(x^2+6)=5^-5x

from a^x =a^y ,<==> x=y

x² +6 = -5x

x² +5x +6 = 0

(x+6)(x-1) = 0

----------- x = -6 or 1

1

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