Find the dimensions of a rectangle with area 343 m² whose perimeter is as small as possible.
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Find the dimensions of a rectangle with area 343 m² whose perimeter is as small as possible.

[From: ] [author: ] [Date: 12-06-26] [Hit: ]
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xy = 343
P = Perimeter = 2x+2y
P = 2x + 686x^-1
dP/dx = 2 - 686/x^2 = 0 for maximum or minimum
2x^2 - 686 = 0
x = 18.52 m
y = 18.52 m

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The minimum perimeter for a rectangle of any given area is a square whose edge measure would be the square root of the area.

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