A cubical block of ice is melting in such a way that each edge decreases steadily by 5.9 cm every hour. At what rate is its volume decreasing when each edge is 2 meters long?
then volume = l^3
dl/dt = 5.9cm/h = .059m/h
dV/dt = dV/dl * dl/dt
= 3l^2 * .059 m/h
at l = 2
dV/dt = -0.708 m/h
I think the answer is correct but it isn't. Where did I make mistakes?
Anyone help me?!!
Thank you.
then volume = l^3
dl/dt = 5.9cm/h = .059m/h
dV/dt = dV/dl * dl/dt
= 3l^2 * .059 m/h
at l = 2
dV/dt = -0.708 m/h
I think the answer is correct but it isn't. Where did I make mistakes?
Anyone help me?!!
Thank you.
-
V = s^3
dV/dt = 3s^2 * ds/dt
dV/dt = 3 * 200^2 * -5.9
dV/dt = -17.7 * 40000
dV/dt = -708000
-708000 cubic cm / h
Your numbers are great, maybe they wanted it in cubic cm instead of cubic meters
dV/dt = 3s^2 * ds/dt
dV/dt = 3 * 200^2 * -5.9
dV/dt = -17.7 * 40000
dV/dt = -708000
-708000 cubic cm / h
Your numbers are great, maybe they wanted it in cubic cm instead of cubic meters