Solve the inequality –2(x – 3) ≥ 5 – (x + 3) and show your work plz.

Multiply out the parentheses on the left:

-2x + 6 >= 5 - (x + 3)

Apply the minus sign to the parentheses on the right:

-2x + 6 >= 5 - x - 3

Combine like terms:

-2x + 6 >= 2 - x

Add x to both sides:

-x + 6 >= 2

Subtract 6 from both sides:

-x >= -4

Multiply through by -1 (remember to flip the inequality sign since that's negative):

x <= 4

-2(x-3)≥5-(x+3)
-2x+6≥5-x+3
-2x+6≥8-x
+2x +2x
6≥x+8
-8 -8
-2≥x
x≤-2

check:
replace x with something in equality (-3)
-2(-3-3)≥5-(-3+3)
12≥5
TRUE

–2 (x –3) ≥ 5 – (x + 3)
–2x + 6 ≥ 5 – x – 3
–2x + x ≥ 2 – 6
–x ≥ –4
x ≤ 4

-2(x-3)≥5-(x+3)
-2x+6≥5-x-3
-2x+6≥2-x
4≥x

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