Very hard differential equation Separating Variables. Help pleaseee

x^2 y y' = e^y

The answer will be
x(y+1) = (1+cx) e^y

The answer you have given to this differential equation is incorrect, you must include the constant of integration in the general solution.

Find the general solution by separating the variables then integrating:
x²yy' = ℮ʸ
x²y(dy / dx) = ℮ʸ
y / ℮ʸ dy = dx / x²
y℮^(-y) dy = dx / x²
∫ y℮^(-y) dy = ∫ 1 / x² dx
-(y + 1)℮^(-y) = -1 / x + C
x(y + 1)℮^(-y) = 1 + Cx
x(y + 1) = (1 + Cx)℮ʸ