If (a+b) / 2 = 36.5 then multiplying by 2
( a + b) = 73 then subtract b from both sides
a = 73 - b this si the result of first equation
Now (ab)^(1/2) = 24 we can square both sides
(ab) = 576 now divide by b
a = 576/b now we can set a=a
73-b = 576/b multiply both sides by b
73b - b^2 = 576 place in order
b^2 -73b + 576 - 0 Solve for b
( b - 64 )(b - 9 )
b = 64 or 9
73-b = a Therefore a is equal to (73 - 64 ) = 9 or (73 - 9) = 64
a= 9 or 64
b= 9 or 64
( a + b) = 73 then subtract b from both sides
a = 73 - b this si the result of first equation
Now (ab)^(1/2) = 24 we can square both sides
(ab) = 576 now divide by b
a = 576/b now we can set a=a
73-b = 576/b multiply both sides by b
73b - b^2 = 576 place in order
b^2 -73b + 576 - 0 Solve for b
( b - 64 )(b - 9 )
b = 64 or 9
73-b = a Therefore a is equal to (73 - 64 ) = 9 or (73 - 9) = 64
a= 9 or 64
b= 9 or 64
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The answer of 9 and 64 is correct. How do you get there?
Solve for a or be in the equation (ab)^(½) =24 and you do that by squaring both sides to get ab = 576. Next solve for either a or b and sub into the other equation (a+b)/2=36.5. But before you do that, get rid of the fraction in that equation since i hate working with fractions. Multiply both sides by 2. Now this equation becomes a + b = 73
Your 2 new equations become
a + b = 73
ab = 576
I'm gona solve for a
a = 576/b and I will substitute for a in the equation a + b = 73 giving you a new equation
576/b + b = 73
Get rid of the fraction by multiplying everything by "b"
b x 576/b + bxb = 73 x b
576 + b^2 = 73b
re-arranging the quadratic I get b^2 -73b + 576 = 0
Factor this quadratic and you will get b =9 and b = 64
Sub one of these into one of your orginial equations for "b" and get a solution for "a".
by th
Solve for a or be in the equation (ab)^(½) =24 and you do that by squaring both sides to get ab = 576. Next solve for either a or b and sub into the other equation (a+b)/2=36.5. But before you do that, get rid of the fraction in that equation since i hate working with fractions. Multiply both sides by 2. Now this equation becomes a + b = 73
Your 2 new equations become
a + b = 73
ab = 576
I'm gona solve for a
a = 576/b and I will substitute for a in the equation a + b = 73 giving you a new equation
576/b + b = 73
Get rid of the fraction by multiplying everything by "b"
b x 576/b + bxb = 73 x b
576 + b^2 = 73b
re-arranging the quadratic I get b^2 -73b + 576 = 0
Factor this quadratic and you will get b =9 and b = 64
Sub one of these into one of your orginial equations for "b" and get a solution for "a".
by th
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A = 9
B = 64
B = 64