t^(6/5) / t^(6/4)
LCD (24/20) - (30/20)
= -6/20 = -3/10
= 10rt t^-3
it's "supposed" to be a positive exponent 3 which is bs because when you divide, aren't you supposed to subtract what's on top to the bottom?
LCD (24/20) - (30/20)
= -6/20 = -3/10
= 10rt t^-3
it's "supposed" to be a positive exponent 3 which is bs because when you divide, aren't you supposed to subtract what's on top to the bottom?
-
apply the rule of exponent . ..
a^b / a^c = a^(b -c)
so,
t^(6/5) / t^(6/4) = t^(6/5 - 6/4)
now, since the exponent is 6/5 and 6/4, take the LCD . ..
5 = 5
4 = 2x 2
LCD =20
hence,
= t^(6/5-6/4)
= t^[ (6*4 - 6*5)/20]
= t^[(24 - 30)/20
= t^(-6/20)
= t^(-3/10)
thus, 1 / (t^3/10) . . .
edit: sorry ash, what i have done is that, i use the law of exponent stated above. .
i subtract the exponent of the bottom to the exponent of the top by getting their LCD which 20 . Then i simplify . .. now, since the exponent of t is -3/10, express the answer which positive exponent by taking the law of negative exponent, that is t^-a is the same as 1/t^a . .
a^b / a^c = a^(b -c)
so,
t^(6/5) / t^(6/4) = t^(6/5 - 6/4)
now, since the exponent is 6/5 and 6/4, take the LCD . ..
5 = 5
4 = 2x 2
LCD =20
hence,
= t^(6/5-6/4)
= t^[ (6*4 - 6*5)/20]
= t^[(24 - 30)/20
= t^(-6/20)
= t^(-3/10)
thus, 1 / (t^3/10) . . .
edit: sorry ash, what i have done is that, i use the law of exponent stated above. .
i subtract the exponent of the bottom to the exponent of the top by getting their LCD which 20 . Then i simplify . .. now, since the exponent of t is -3/10, express the answer which positive exponent by taking the law of negative exponent, that is t^-a is the same as 1/t^a . .