Finding the value of x help!

1) find all the values of x, ( 2/ x-3) ² -3(2/ x-3)-4=0

2) Find all the values of x, ( √2x + 2) - (√x + 2 ) = 1

3) Find all the values of x, log₄x = - 3/2

(1) (2 / x - 3)² -3(2 / x - 3) - 4 = 0

4/(x - 3)² - 6(x - 3) / (x - 3)² = 4

22 - 6x/(x - 3)² = 4

22 - 6x = 4(x - 3)²

22 - 6x = 4x² - 24x + 36

4x² - 18x + 14 = 0

(4x - 14)(x - 1) = 0

x = 7/2 or 1.


(2) (√2x + 2) - (√x + 2) = 1

√2x - √x = 1

2x² - x = 1

2x² - x - 1 = 0

(2x + 1)(x - 1) = 0

x = -1/2 or 1


(3) log_4(x) = -3/2

x = 4^(-3/2) = 1/8