Can someone tell me if I'm doing this right? Pre-Calc Trig

A pendulum in a grandfather clock is 4 feet long and swings back and forth along a 6-inch arc. Approximate the angle (in degrees) through which the pendulum passes during one swing.

So...This is what I did:
r = 4ft.
S = 6 in.

I converted 4ft into inches, so..

r = 48 in.
S = 6 in.

then I did s=theta times r, so: 6=theta x 48.
And then theta= 1/8 or .125

And then because that's in radians, I did
.125(180/pi)

and I got, 7.16.

I don't think that's correct though. If it's not, can someone do it the right way please?

You are indeed correct.

Alternate method:

Circle has radius = 48 in
circumference = 2πr = 96π in
arc length = 6 in

6/(96π) = θ/360 . . . . where θ is angle in degrees
θ = 360 * 6/(96π) = 7.161972439

Ok imagine your pendulum is in a circle with a radius of 48 inches.
C = π(48)(2) (circumference)
C = 96π

set the arc length over the circumference equal to the angle 𝜽 over 2π radians. Like so:

6/96π = 𝜽/2π

or

6 𝜽
––– = ––
96π 2π

then cross multiply.

𝜽 = 12π/96π
= 1/8 rad
= 7.16°

oh. I guess you already knew that though. Glad I couldn't help.

Your answer is correct.

you are correct