Maths: Quadratic function. I've answered up to a(iv) but i don't know how to do anymore please help

Consider the quadratic function f (x) = –x^2 + 5x – 2. The average rate of change of this function between any two points (x, f (x)) and (x + h, f (x + h)) can be calculated using the so-called difference quotient
f (x + h) – f (x) / h
where h is known as the step size (or the increment).

(a) Use this difference quotient to calculate the average rate of change of this quadratic function between
(iv) x = 2 and x = 2+ h

Do NOT round your answers. Note that your answer to part (iv) will be an algebraic expression, not a numerical value. Simplify this expression.

(b) Use your answer to part (a)(iv) to answer the following question:
As h approaches 0, what numerical value does
f (2 + h) – f (2),
h
approach?

(c) Now use calculus to find

(i) The derivative function f '(x)

(ii) The value f '(2)

(d) Compare f '(2) with your answer to part (b). Explain why these two values are equal or not equal.
(e) Draw the graph of the function for the domain 0 ≤ x ≤ 5 . On your graph roughly draw by hand the tangent line passing through the point (2, f (2)) . What is the gradient of this tangent line?

b) -h^2 +h+8

c) (i) -2x+5
(ii) 1

hope this helps