Prove algebraically that the equation is an identity
Favorites|Homepage
Subscriptions | sitemap
HOME > > Prove algebraically that the equation is an identity

Prove algebraically that the equation is an identity

[From: ] [author: ] [Date: 12-11-12] [Hit: ]
......
Can someone please help me through this?

[csc(x)] / [cos(x)] - [cos(x)] / [sin(x)] = tan(x)

-
[csc(x)] / [cos(x)] - [cos(x)] / [sin(x)]

---csc(x) = 1 / [sin(x)], so [csc(x)] / [cos(x)] = 1 / [sin(x)cos(x)]

1 / [sin(x)cos(x)] - [cos(x)] / [sin(x)]

---multiply top and bottom of [cos(x)] / [sin(x)] by cos(x)

1 / [sin(x)cos(x)] - ([cos(x)]^2) / [sin(x)cos(x)]
(1 - [cos(x)]^2) / [sin(x)cos(x)]

---[sin(x)]^2 + [cos(x)]^2 = 1, so 1 - [cos(x)]^2 = [sin(x)]^2

[sin(x)]^2 / [sin(x)cos(x)]
[sin(x)] / [cos(x)]

--- tan(x) = [sin(x)] / [cos(x)]

tan(x)
1
keywords: an,that,identity,algebraically,is,Prove,equation,the,Prove algebraically that the equation is an identity
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .