How do you solve this problem (10 points for best answer)

lim (x+1) / √(x+2) - 1
x -> -1


Any help or advice would be much appreciated.

apply L-hospital rule

since u r getting 0/0 after applying the limit

so differentiating both numerator and denominator u will get

lim 1/[1/2√(x+2) ] or
x -> -1

lim 2√(x+2)
x -> -1

after applying the limit u will the answer as 2

Sujeet Kumar got it right if you meant
lim (x+1) / [√(x+2) - 1]
x -> -1

But if it's like this:
lim (x+1)/√(x+2) - 1
x -> -1
(where -1 isn't part of the fraction) you have 0/√1 -1 = -1.

I dont know...
Just leave it (if its homework), get your parents to write a note saying that you cant do it, then get your teacher to explain it to you. Hope you solve it!

your limit is in the form of 0/0; Applying L'Hospital's rule, you may get Lt {x->-1} 1/[1/(2√(x+2))] = 2