How to differentiate 1/(x^5) using First Principle

Please give a proper solution

Jakey boy its the same as before.

[(1 / (x+h)^5) - (1/x^5)] / h

(x^5 - (x+h)^5) / (x+h)^5 (x^5) h

(x^5 - (x^5 + 5x^4h + 10x^3h^2 + 10x^2h^3 + 5xh^4 + h^5)) / [(x+h)^5 (x^5) h]

-(5x^4h + 10x^3h^2 + 10x^2h^3 + 5xh^4 + h^5) / [(x+h)^5 (x^5) h]

Cancel an h:
[-5x^4 - 10x^3h - 10x^2h^2 - 5xh^3 - h^4] / [(x+h)^5 (x^5)]

Take limit as h -->0
[-5x^4] / (x^5)(x^5)

Cancel an x^4:
(-5) / (x^6)

Check by direct differentiation:
d/dx (x^-5) = -5x^-6 = -5/x^6 :)

d/dx [ 1 / x^5 ] = lim h ---> 0 [ 1 / (x+h)^5 - 1 / x^5] / h =

lim h ---> 0 [ (x^5 - (x+h)^5) / [h * (x+h)^5 * x^5] =

lim h ---> 0 [ (x^5 - (x^5 + 5hx^4 + 10h^2 x^3 + 10h^3 x^2 + 5h^4 x + h^5)) / [h * (x+h)^5 * x^5] =

lim h ---> 0 [ ( - (5x^4 + 10h x^3 + 10h^2 x^2 + 5h^3 x + h^4)) / [(x+h)^5 * x^5] =

Evaluate for h = 0 ---->> [ ( - (5x^4 + 10h x^3 + 10h^2 x^2 + 5h^3 x + h^4)) / [(x+h)^5 * x^5] =

[ ( - (5x^4 + 0 + 0 + 0 + 0)) / [(x+0)^5 * x^5] = - 5x^4 / x^10 = - 5 / x^6

(f(x+h)-f(x))/h
=(1/(x+h)^5 - 1/x^5)/h