Find x by use of determinant: 3x-4y+2z+8=0, x+5y-3z+2=0, 5x+3y-z+6=0, pls i need explanation. Tnx

3x-4y+2z=-8
x+5y-3z=-2
5x+3y-z=-6

Cramer's rule
determinant of coefficients
A =
3,-4,+2
1,+5,-3
5,+3,-1

det A = 24

now write a new matrix Ax replacing the first column of A with the column of the numbers in right hand sides of the equations -8,-2,-6

Ax =
-8,-4,+2
-2,+5,-3
-6,+3,-1

det Ax = -48

x = (det Ax)/(det A) = - 48/24 = - 2

if you need y then you replace numbers column in the second column of A
and to find z in the third

x = -2,y = 3,z = 5

I believe X is = to 10.

X = 10; Y = 7; Z = -5

(3 x 10) - (4 x 7) + (2 x -5) + 8 = 0

30 - 28 = 2

2 + (2 x -5) = -8

2 + -10 = -8

-8 + 8 = 0