In the circuit shown in the figure (Figure 1) both batteries have insignificant internal resistance and the idealized ammeter reads 2.00A in the direction shown.
http://session.masteringphysics.com/prob…
A) Find the emf of the battery.
10 points, thanks!
http://session.masteringphysics.com/prob…
A) Find the emf of the battery.
10 points, thanks!
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Apply Kirchoff's voltage law and current law the given circuit.
Name the branch which contains 75volts cell as AB. The branch contains 12 ohm resistor as AC. Then name the branch which contains 48ohm resistor as CD. The remaining branch as FE(top F).
Apply KVL to the loop ABCDA. Then we get,
75 - 12x2 - (2 -i) 48 = 0
Solving the above we get, i = 0.94A. The balance current (2 - 0.94) flows into the branch CD.
Now apply KVL to the loop CDEFC. We get,
- E -15x0.94 + 48x 1.06 = 0, on solving for E we get,
E = 36.78volt
Name the branch which contains 75volts cell as AB. The branch contains 12 ohm resistor as AC. Then name the branch which contains 48ohm resistor as CD. The remaining branch as FE(top F).
Apply KVL to the loop ABCDA. Then we get,
75 - 12x2 - (2 -i) 48 = 0
Solving the above we get, i = 0.94A. The balance current (2 - 0.94) flows into the branch CD.
Now apply KVL to the loop CDEFC. We get,
- E -15x0.94 + 48x 1.06 = 0, on solving for E we get,
E = 36.78volt