the sum of ages of a father and son is 56 and 4 years ago th
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the sum of ages of a father and son is 56 and 4 years ago th

[From: Mathematics] [author: ] [Date: 01-07] [Hit: ]
the sum of ages of a father and son is 56 and 4 years ago the father was 3 times as old as his son so whats the ages at the moment?Thanks?......


the sum of ages of a father and son is 56 and 4 years ago the father was 3 times as old as his son so whats the ages at the moment?Thanks?

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answers:
RR say: The sum of ages of a father and son is 56
f + s = 56

.. and 4 years ago the father was 3 times as old as his son

(f - 4) = 3(s -4)
f - 4 = 3s - 12
f - 3s = -8

You have a simultaneous equation:
(i) f + s = 56
(ii) f - 3s = -8

subtract (ii) from (i) to eliminate f (remember when you subtract a minus it becomes a plus)
4s = 64
s = 16

Substitute into (i)
f + 16 = 56
f = 40

ANS Father = 40, Son = 16.
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Φ² = Φ+1 say: The father is (56 - 8)(3/4) + 4 = ___ years old and the son is (56 - 8)(1/4) + 4 = ___ years old.
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JG say: Let f and s be the dad's and the son's ages respectively
f + s = 56
f-4 = 3(s-4)
f-4=3s-12
f-3s=-8
f=3s-8
3s-8+s=56
4s=64
s=16
f+16=56
f=40

The dad is 40 and the son is 16.
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Como say: f + s = 56
f - 4 = 3 ( s - 4 )
f - 4 = 3s - 12

f - 3s = - 8
f + s = 56

4s = 64
s = 16_______son
f = 40_______father
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TomV say: f = age of father
s = age of son

s+f = 56 → s = 56-f
f-4 = 3(s-4)

f - 4 = 3(52-f)
4f = 160
f = 40
s = 16

Ans: Father is 40 years old and Son is 16

(Four years ago, they were 36 and 12, respectively, a ratio of 3:1)
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david say: 4 years ago .. father's age = y, son'd age = x
y = 3x
Now .. father;s age = (y + 4) ... and son's age = (x + 4)
(y + 4) + (x + 4) = 56
3x + 4 + x + 4 = 56
4x = 48
x = 12, ... y = 36
ages now x + 4 = 16
y + 4 = 40
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Steve A say: f +s = 56
s = 56 -f
f -4 = 3(s -4)
f -4 = 3(56 -f -4)
f -4 = 3(52 -f)
f -4 = 156 -3f
4f = 160
f = 40
s = 56-40 = 16
They are 40 and 16.
They were 36 and 12.
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rsrtp say: nmromtbk
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jvbtl say: ccdrwpdr
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bjvlt say: iglsefmk
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say: Let the father's age be F
Let the son's age be S
F+S = 56---(1)
4 years ago,
(F-4)=3(S-4)
F-4=3 S-12
F - 3 S = -8--(2)
From (1),
F = 56 - S
put F= 56 - S in (2),
56 - S - 3 S = - 8
56 - 4 S = - 8
-4 S = - 8 - 56
4 S = 64
S = 16

Son's age = 16
Father's age = 56 - 16 = 40
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Damien say: 26 and 30
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jrdbh say: dqdxnvfl
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livi say: 56 - 8 (4 years ago times two people) = 48

48 = 3x + x
48 = 4x
48/4 = 12
x = 12

12 * 3 = 36
12 + 4 = 16
36 + 4 = 40

they are 40 and 16.
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kxwxd say: birwurhd
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ftdvl say: jqpduzag
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vjdfp say: jgbjuwis
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pjzjt say: ctldfpvd
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