the answer comes out as
root3 sin(2t)/ sin(t)
however,
I ended up with
root3 sin(2t)/ 2sint(t)
can anyone help

answers:
Ray say: dx/dt = 2sin t
dy/dt = 6sin 2t
dy/dx = (dy/dt) (dt/dx)
dy/dx = (6sin 2t) (2sin t)
dy/dx = (3sin 2t) / (sin t)
So have you stated the question correctly ?

rotchm say: If u got the wrong answer, show your steps so we can show u where u erred.
dt/dx = (dy/dt) / (dx/dt)

mzols say: jzpzbawe
