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Exact value root of f(x)= 5x^2 + 12x - 5?

## Exact value root of f(x)= 5x^2 + 12x - 5?

[From: Mathematics] [author: ] [Date: 01-07] [Hit: ]
Exact value root of f(x)= 5x^2 + 12x - 5?......

Exact value root of f(x)= 5x^2 + 12x - 5?

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sepia say: f(x) = 5x^2 + 12x - 5
x = -6/5 - sqrt(61)/5
x = sqrt(61)/5 - 6/5
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la console say: 5x² + 12x - 5 = 0

5x² + 12x = 5

x² + (12/5).x = 1

x² + (12/5).x + (6/5)² = 1 + (6/5)²

x² + (12/5).x + (6/5)² = (25/25) + (36/25)

x² + (12/5).x + (6/5)² = 61/25

[x + (6/5)]² = [± (√61)/5]²

x + (6/5) = ± (√61)/5

x = - (6/5) ± [(√61)/5]

x = (- 6 ± √61)/5

x₁ = (- 6 + √61)/5

x₂ = (- 6 - √61)/5
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Morningfox say: The standard quadratic equation will work here (like it does for ALL quadratic equations).
root = [-b +/- sqrt( b^2 - 4ac) ] / ( 2a)
root = [-12 +/- sqrt( 12^2 - 4*5*(-5)) ] / ( 2(5))
root = -1.2 +/- 0.2 sqrt( 61)
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RealPro say: Yeah that makes no sense so you should explain the question better.
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ifivx say: nfqdkgpn
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hdcez say: ygqlbrge
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