How do I factor these? I think I got the first one. The first being (4n^4z^2-7p)x(16^8z^4+28n^4pz^2+49p^2)?

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answers:
Krishnamurthy say: Factor:
1)
64n^12z^6 - 343p^3
= (4n^4z^2)^3 - (7p)^3
= (4 n^4 z^2 - 7 p) (16 n^8 z^4 + 28 n^4 p z^2 + 49 p^2)
2)
x^(8pq) - y^(4n)
= (x^(2 p q) - y^n) (y^n + x^(2 p q)) (y^(2 n) + x^(4 p q))
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mizoo say: a^3 - b^3 = (a - b)(a^2 + ab + b^2)

64n^12z^6 - 343p^3 = (4n^3z^2)^3 - (7p)^3

= (4n^4z^2 - 7p)((4n^3z^2)^2 + 4n^4z^2 * 7p + (7p)^2)

= (4n^4z^2 - 7p)(16n^8z^4+ 28n^4z^2p + 49p^2)
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